Calculating Forces and Magnitude for a 2.50 kg Block on a Frictionless Table

  • Thread starter Thread starter collegegirl13
  • Start date Start date
  • Tags Tags
    Forces Magnitude
AI Thread Summary
To determine the normal force on a 2.50 kg block pushed by a 17.0 N force at an angle of 22.6° below the horizontal, the forces acting in the vertical direction must be analyzed. The gravitational force acting on the block is 24.50 N downward, while the applied force has both vertical and horizontal components. Since there is no vertical movement, the sum of the vertical forces must equal zero, allowing for the calculation of the normal force. The horizontal component of the applied force contributes to the net force on the block, which can be calculated using the resolved components. Properly setting up a free body diagram (FBD) is essential for visualizing and solving these forces.
collegegirl13
Messages
6
Reaction score
0
A block of mass 2.50 kg is pushed 2.18 m along a frictionless horizontal table by a constant 17.0 N force directed 22.6o below the horizontal.

Determine the magnitude of the normal force exerted by the table.
and
Determine the net force on the block.

I already found that the work done by the applied force is 3.42×101 J and the magnitude of the force of gravity is 24.50 N. I just don't know what to do to find the other two, I have tried several different equations but none of them are seeming to work for me...
 
Physics news on Phys.org
Have you set up a FBD? If you do, you'll see that there's three forces that at least partly act in the y-direction. There's no movement in the y-direction, which tells you what about the forces?
 
You need to resolve the Force applied into normal and parallel to the surface components.

That's where the 22.6° angle comes in.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggle to understand the concept of the question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Vector problem, magnitude of the force
Replies
30
Views
2K
Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
Distribution of Energy when work is done on a system of 2 masses connected by a spring
Replies
17
Views
2K
Calculating Net Force on a Wheel: Magnitude and Direction | 0.350 m Radius
Replies
4
Views
2K
Magnitude of Force Exerted on Middle Block in a Three-Block System
Replies
14
Views
4K
Forces on a Block and Friction on a Surface
Replies
8
Views
2K
Pushing down on a block at an angle on a horizontal table with friction
Replies
7
Views
2K
Force of a block on an incline above a horizontal
Replies
10
Views
2K
Two blocks on a frictionless surface; find the force
Replies
3
Views
5K
A frictionless incline with a block sliding down it....
Replies
2
Views
3K

Hot Threads

Recent Insights

Back
Top