Calculating Forces, Mass & Velocity: A Homework Challenge

AI Thread Summary
The discussion focuses on solving a physics homework problem involving three forces acting on an object. Participants clarify that to find the direction of acceleration, the resultant force must be calculated by summing the x and y components of the given forces. The acceleration is determined to be 3.70 m/s², and the direction is approximately 144 degrees from the positive x-axis. To find the velocity components after 16 seconds, the relationship between the magnitude of velocity and its components is discussed, leading to a system of equations based on trigonometric relationships. The conversation emphasizes the importance of vector addition and the use of arctangent for determining angles in vector problems.
zcabral
Messages
30
Reaction score
0

Homework Statement


Three forces acting on an object are given by F1 = ( 1.55 i - 1.90 j ) N, F2 = ( - 5.20 i - 3.15 j ) N, and F3 = ( - 50.0 i + 44.0 j ) N.
(a) What is the direction of the acceleration?
° (from the positive x axis)
(b) What is the mass of the object?
kg
(c) If the object is initially at rest, what is its speed after 16.0 s?
m/s
(d) What are the velocity components of the object after 16.0 s?
( i + j ) m/s

Homework Equations



F=ma

The Attempt at a Solution



the acceleration is 3.70 m/s2. i know to get the direction in part (a) i have to use arctan ay/ax but i can't figure out how to get those values. the velocity is 59.2m/s but i don't know how to get the unit vectors.
 
Last edited:
Physics news on Phys.org
You need to add the 3 vectors vectorally. So add up the i components for your resultant x-value, and add up your j's for the resultant y-value. Then to get the direction, use the arctan. This should get you going.

To get unit vectors you need to divide each coordinate by the magnitude of the resultant vector.

Chris
 
Last edited:
I'm assuming the acceleration is given?(you stuck it in the solution part so I'm not sure if it's something you figured out but I think it's given, considering the problem)

So what's the resultant force? You just add F1+F2+F3=Fr, those are all vectors so add the x and y components separately. Then that's the y and x component you use in your arctan equation.

You know the magnitude of the acceleration, so if you find the magnitude of that resultant force you can use F=ma to find m

Knowing a I assume you solved c correctly, so...

Edit: That guy's way for d is obviously the better way than what I typed >_>
 
Last edited:
ok i figured out the direction is 144 degress approximately. however i still don't get how to find the components of velocity (not acceleration)
 
Actually maybe what I deleted up there was what we needed. Aw what the heck, I'll throw it out here

You know velocity's magnitude, you want the x and y components Vx and Vy

We know sqrt(Vx^2+Vy^2)=|V|(and you know |V|)

We also know the angle(because the velocity will be in the same direction as the force)

so tan(that angle)=Vy/Vx, tan(that angle)=some# so Vy=some#*Vx, and you can plug that back into the other equation and solve for Vy, then find Vx
 
ok but i still don't get how to find vy and vx, obviously system of equations but won't that make it tan 144=0?
 
Why would that happen? tan(144)=-.727, so -Vx*.727=Vy

so sqrt[(-Vx*.727)^2+Vx^2]=|V|, solve for Vx, then put that back into -Vx*.727=Vy to solve for Vy
 
Back
Top