Calculating Forces of Friction with Coefficient of 0.544 and Weight of 86.5N

AI Thread Summary
To calculate the horizontal forces acting on the center board, the normal force is determined by multiplying the weight (86.5N) by the acceleration due to gravity (9.8 m/s²), resulting in 847.7N. The force of friction is then calculated using the coefficient of friction (0.544) multiplied by the normal force. This yields the horizontal forces needed to prevent the board from slipping. Clarification is requested for the calculation process, and a visual aid would be helpful for understanding. Accurate calculations are essential for ensuring stability in this scenario.
Momentum09
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The board which weighs 86.5N is sandwiched between two other boards. If the coefficient of friction between the boards is 0.544, what must be the magnitude of the horizontal forces acting on both sides of the center board to keep it from slipping downward?



2. Force of friction = coefficient x Normal force
Normal force = mg



3. I first found out what the normal force is by multiplying 86.5 by 9.8 = 847.7. Do I then find the horizontal forces by multiplying that value by the coefficient?

Thank you so much.
 
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it would be eaiser if you supplied a picture.
 
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