Calculating Friction Force on a Resting Block

AI Thread Summary
A 1.2 kg block resting on a horizontal surface has a coefficient of static friction of 0.5. When a 9.8 N external force is applied, it exceeds the maximum static friction force of 5.88 N, indicating the block will move. The discussion highlights that if the applied force is greater than the static friction limit, kinetic friction takes over, making the static friction coefficient irrelevant. To determine the force of kinetic friction, the coefficient of kinetic friction must be known, which can be measured. The conversation emphasizes the importance of understanding the transition from static to kinetic friction in this scenario.
physaru86
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A 1.2 kg block is resting on horizontal surface. The coefficient of static friction between block and
surface is 0.5. What is the magnitude and direction of force of friction on block when magnitude of external force acting of block in the horizontal direction is 9.8 N
fs = μs*N, N = mg
upload_2015-3-31_18-52-3.png


m = 1.2 kg, μs = 0.5, g = 9.8
fs = 0.5*1.2*9.8 N = 5.88 N
 
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Is this really the full problem statement, exactly as presented, because something seems wrong about it.

Chet
 
Chestermiller said:
Is this really the full problem statement, exactly as presented, because something seems wrong about it.

Chet
please tell me what is wrong about it?
 
If the applied force is less than the normal force times the coefficient of static friction, then the friction force will equal the applied force and the body will not move. If the applied force is equal to the normal force times the coefficient of static friction, then the friction force will equal the applied force and the body will be on the verge of moving. But, in your example, the applied force is greater than the normal force times the coefficient of static friction, so the body will move, and kinetic friction will prevail; in this case, the coefficient of static friction is irrelevant, as is the normal force times the coefficient of static friction.

Chet
 
S
Chestermiller said:
If the applied force is less than the normal force times the coefficient of static friction, then the friction force will equal the applied force and the body will not move. If the applied force is equal to the normal force times the coefficient of static friction, then the friction force will equal the applied force and the body will be on the verge of moving. But, in your example, the applied force is greater than the normal force times the coefficient of static friction, so the body will move, and kinetic friction will prevail; in this case, the coefficient of static friction is irrelevant, as is the normal force times the coefficient of static friction.

Chet
So can the force of kinetic friction be found? if so how to find
 
physaru86 said:
S

So can the force of kinetic friction be found? if so how to find
To find that, you need to know the coefficient of kinetic friction.

Chet
 
Chestermiller said:
To find that, you need to know the coefficient of kinetic friction.

Chet
Yes it was the same doubt i had. can the coefficient of kinetic friction be found
 
physaru86 said:
Yes it was the same doubt i had. can the coefficient of kinetic friction be found
Sure, it can be measured.

Chet
 
Chestermiller said:
Sure, it can be measured.

Chet
thanks
 
  • #10
Oposed to motion
 
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