Calculating Heat Energy Changes in a Water and Ice System

AI Thread Summary
The discussion revolves around calculating heat energy changes in a water and ice system, focusing on three main problems: the heat lost by the water, the energy gained by the melted ice, and the heat required to melt the ice. The initial data includes the mass of the cup, the initial and final masses of water, and temperature changes. A participant calculated the heat lost by the water as 22,264 J but expressed uncertainty about the accuracy and methodology for the other calculations. Clarifications were sought regarding the cup's material and the initial temperature of the ice, with a consensus to assume the ice starts at 0°C. The conversation emphasizes the importance of showing calculations clearly and using symbols before plugging in numbers.
Ravi Ramdoolar
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Homework Statement


mass of cup 1.78g
initial mass of water and cup - 54.26g
finlal mass of water after ice added - 91.26g
initial temperature - 27°C
temperature after heated - 92°C
temperature after ice added - 35°C

problem
1) how much heat energy did the original mass of water lose?
2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
3)calculate the amount of heat energy required to melt the ice

Homework Equations



Q = mcΔθ
Q = mLv

The Attempt at a Solution



1) Q= .093 × 4200×57 = 22264 J

I am not sure if this is correct i don't know what to do for the other two including this one could someone help me please :confused:
 
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Ravi Ramdoolar said:

Homework Statement


mass of cup 1.78g
initial mass of water and cup - 54.26g
finlal mass of water after ice added - 91.26g
initial temperature - 27°C
temperature after heated - 92°C
temperature after ice added - 35°C

problem
1) how much heat energy did the original mass of water lose?
2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
3)calculate the amount of heat energy required to melt the ice

Homework Equations



Q = mcΔθ
Q = mLv

The Attempt at a Solution



1) Q= .093 × 4200×57 = 22264 J

I am not sure if this is correct i don't know what to do for the other two including this one could someone help me please :confused:
Welcome to PF Ravi.

First you should give us the complete problem as written. There is some information missing here. What is the cup made of? Second, you must explain your reasoning and tell us where you get these numbers.

AM
 
Andrew Mason said:
Welcome to PF Ravi.

First you should give us the complete problem as written. There is some information missing here. What is the cup made of? Second, you must explain your reasoning and tell us where you get these numbers

AM

the cup is made out of styro foam an it was an experiment an that was the results
 
Ravi Ramdoolar said:
initial temperature - 27°C
How is that relevant?
2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
Are you sure the ice was at 0C?
1) Q= .093 × 4200×57 = 22264 J
It's not at all clear where you are getting those numbers from. It's much better to do the working in symbols, only plugging in numbers at the end. At the least, please show how each of those numbers comes from your raw data.
 
haruspex said:
How is that relevant?

Are you sure the ice was at 0C?

It's not at all clear where you are getting those numbers from. It's much better to do the working in symbols, only plugging in numbers at the end. At the least, please show how each of those numbers comes from your raw data.
just please take the ice as 0°C
 
Ravi Ramdoolar said:
just please take the ice as 0°C

an the initial temperature was 27°C of the water beforeheat was applied
 
Ravi Ramdoolar said:
an the initial temperature was 27°C of the water beforeheat was applied
Yes, I understand that, but I don't see how it is relevant to the questions. They all seem to concern what happened after the water had been heated.
 
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