Calculating Heat Transfer: Specific Heat Homework"

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The discussion focuses on calculating the specific heat of a metal using heat transfer principles. The specific heat of water is given as 4.187 J/g.K, and the participant outlines their calculations for heat released by the metal and heat absorbed by both water and the container. They equate the total heat released to the total heat absorbed, leading to a calculated specific heat of the metal at 0.3156 J/g.K. The calculations appear to be reasonable based on the provided values and formulas. The participant seeks confirmation on the accuracy of their work.
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Homework Statement



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Homework Equations


Is my work right? This is the last attempt I got :/

The Attempt at a Solution


Specific heat of water = 4.187 J/g.K
Heat released by hot metal = mass x specific heat x temperature change
= 99 x c x (100 - 21.4) = 7781.4c
Heat absorbed by water = mass x specific heat x temperature change
= 403 x 4.187 x (21.4 - 20.0) = 2362.305 J
Heat absorbed by container = mass x specific heat x temperature change
= 212 x c x (21.4 - 20.0) = 296.8c
Total heat released = total heat absorbed
7781.4c = 2362.305 + 296.8c
Specific heat of the metal = c = 0.3156 J/g.K = 0.3156 kJ/kg.K
 
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Looks reasonable.
 
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