Calculating Horizontal Distance for a Falling Object Without an Angle

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To calculate the horizontal distance a book travels after being shoved off a table, first determine the time it takes to fall from the table height of 1.2 m using the formula h = (1/2)gt^2, which gives approximately 0.49 seconds. The book's horizontal velocity can be found using v = at, resulting in a velocity of 6.5 m/s after 5 seconds of acceleration at 1.3 m/s². The horizontal distance is then calculated by multiplying this velocity by the time of fall, yielding a distance of 3.22 m. The key point is that the initial vertical velocity is zero since the book only has a horizontal component when it begins to fall. This approach effectively separates the horizontal and vertical motions to arrive at the correct answer.
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Homework Statement


A girl shoves a book at rest on a table and it moves with an acceleration of 1.3 m/s . After 5 s, the book falls at the edge of the table. If the table height is 1.2 m, find the horizontal distance that it hit the floor. (ans: 3.22 m) ... How the answer would be 3.22

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The Attempt at a Solution



Actually in this question doesn't have the angle .. So is it right to choose the maximum height formula so I can have the angle and then apply the Horizonte distance which is v0^2 sin2(q)/g
Tq
 
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I would break the problem into two parts, horizontal and vertical motion.

You know the height and the initial vertical velocity. How long in seconds does it take to hit the ground?

Calculate the horizontal velocity. How far does it travel horizontally in the same time?
 
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The angle is simply zero cause the velocity of the book, just before it starts falling, is horizontal.
 
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CWatters said:
I would break the problem into two parts, horizontal and vertical motion.

You know the height and the initial vertical velocity. How long in seconds does it take to hit the ground?

Calculate the horizontal velocity. How far does it travel horizontally in the same time?


Which formula for both parts ?
 
Yeah ..I just solve it thank so much
First we find the velocity from this formula v=at
Then we apply to find the time that it take to hit the ground which from this formula y=y0+v0y(t)+(1/2)gt^2
Finally we just multiply between the velocity from the answer 1 (6.5) and time 0.16

Is it right ??
 
well yes and no. The time it takes from the moment it passes the edge of table to the moment it hits the ground isn't 0.16 according to my calculations. Just use h=(1/2)gt2
 
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Ooh so the time will be 0.49 s

Sorry
 
yes but still you have to understand something, when you wrote the equation for y, y=y_0+v_{0y}t+(1/2)gt^2 it is v_{0y}=0 cause the book starts its fall with only horizontal velocity component.
 
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