Calculating Horizontal Speed of a Stealth Bomber

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To calculate the horizontal speed of a stealth bomber that drops a bomb from 3500m and travels 1.25 km horizontally, the time of fall must first be determined using the equation for free fall. The time taken for the bomb to hit the ground can be calculated using the formula for gravitational acceleration. For the brick thrown at a 25-degree angle with an initial speed of 15 m/s, the height of the building can be found using projectile motion equations. The discussion emphasizes the need for understanding kinematic equations to solve these problems effectively. Overall, both scenarios require applying principles of physics related to projectile motion and free fall.
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a stealth bomber on a training mission drops one of its bombs from a height of 3500m during level flight. The bomb travels a horizontal distance of 1.25 km. What was the plane's horizontal speed?



a brick is thrown upward from the top of a building at an angle of 25 degrees to the horizontal and with an initial speed of 15 m/s. it strikes the ground below. if teh brick is in flight for 3.0 s, how tall is the building?


i don't know the equation or the answer, can someone provide both for me?
 
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read the rules about homework questions and try again.

hint: the projectile motion equations are usually found under kinematic equations or just kinematics.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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