Calculating Impulse in a Collision

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SUMMARY

The discussion focuses on calculating impulse during a collision involving a 26 kg object with initial velocity of +10 m/s. The impulse is determined using the formula Impulse = mass * change in velocity. For the final velocity of +8.0 m/s, the impulse calculated is 52 kg·m/s, while for -8.0 m/s, the impulse is 468 kg·m/s. A correction was made regarding the initial and final velocities in the calculations.

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  • Understanding of impulse and momentum concepts
  • Familiarity with the formula for impulse: Impulse = mass * change in velocity
  • Basic knowledge of physics equations related to motion
  • Ability to perform calculations involving mass and velocity
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itsmarasilly
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Homework Statement



Before a collision, a 26 kg object is moving at +10 m/s. Find the impulse that acted on the object if, after the collision, it moved at the following velocities.

a) +8.0 m/s
b) -8.0 m/s


Homework Equations



Impulse = change in momentum
= mass * change in velocity
= m * (vf - vi)

The Attempt at a Solution



a) = 26 (+10 m/s - +8.0 m/s), impulse = 52?
b) = 26 (+10 m/s - -8.0 m/s), impulse = 468?
 
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Hi itsmarasilly,

itsmarasilly said:

Homework Equations



Impulse = change in momentum
= mass * change in velocity
= m * (vf - vi)

The Attempt at a Solution



a) = 26 (+10 m/s - +8.0 m/s), impulse = 52?
b) = 26 (+10 m/s - -8.0 m/s), impulse = 468?


If you compare these to the last equation in your "Relevant equations" section, it looks like you have the initial and final velocities switched.
 
oh okay, got it. thanks! :)
 

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