Calculating Impulse in a Collision

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To calculate the impulse acting on a 26 kg object during a collision, the change in momentum is determined using the formula Impulse = mass * change in velocity. For the first scenario, where the object slows from +10 m/s to +8.0 m/s, the impulse is calculated as 52 kg·m/s. In the second scenario, where the object reverses direction to -8.0 m/s, the impulse is found to be 468 kg·m/s. A correction was noted regarding the initial and final velocities in the calculations. Accurate impulse calculations are essential for understanding momentum changes in collisions.
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Homework Statement



Before a collision, a 26 kg object is moving at +10 m/s. Find the impulse that acted on the object if, after the collision, it moved at the following velocities.

a) +8.0 m/s
b) -8.0 m/s


Homework Equations



Impulse = change in momentum
= mass * change in velocity
= m * (vf - vi)

The Attempt at a Solution



a) = 26 (+10 m/s - +8.0 m/s), impulse = 52?
b) = 26 (+10 m/s - -8.0 m/s), impulse = 468?
 
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Hi itsmarasilly,

itsmarasilly said:

Homework Equations



Impulse = change in momentum
= mass * change in velocity
= m * (vf - vi)

The Attempt at a Solution



a) = 26 (+10 m/s - +8.0 m/s), impulse = 52?
b) = 26 (+10 m/s - -8.0 m/s), impulse = 468?


If you compare these to the last equation in your "Relevant equations" section, it looks like you have the initial and final velocities switched.
 
oh okay, got it. thanks! :)
 
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