Calculating Impulse of a Bouncing Steel Ball | Momentum and Impulse Homework

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The problem involves calculating the impulse of a steel ball with a mass of 0.347 kg that bounces after falling. The ball's speed before impact is 23.6 m/s, and after bouncing, it is 12.7 m/s. The impulse is calculated using the formula J = pf - pi, resulting in an impulse of 12.6 kg*m/s. The direction of the momenta is crucial in this calculation. The answer appears to be correct based on the provided values and calculations.
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Homework Statement


A steel ball with mass 0.347 kg falls onto a hard floor and bounces. Its speed just before hitting the floor is 23.6 m/s and its speed just after bouncing is 12.7 m/s. (a) What is the magnitude of the impulse of the ball?


Homework Equations


J=pf-pi


The Attempt at a Solution


J=.347kg(12.7m/s)-.347kg(-23.6m/s)
J=12.6kg*m/s
 
Last edited:
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Please take note of the direction of the momenta that you are considering.
 
Would anybody check this new answer?
 
Looks correct to me :)
 
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