Calculating Induced EMF in a Conducting Loop with Changing Magnetic Field

AI Thread Summary
To calculate the induced EMF in the conducting loop, use the equation for induced EMF, which is -dflux/dt, where flux is the product of the magnetic field B(t) and the area of the half circle. The magnetic field B(t) is given as a function of time, and you must add this induced EMF to the battery's EMF of 2.0V to find the total EMF in the loop. The direction of the induced EMF can be determined using Lenz's Law, which states that the induced current will oppose the change in magnetic flux. Finally, apply Ohm's Law (V = iR) to calculate the current in the loop at t = 10 seconds. Understanding these principles will help solve the problem effectively.
Moore65
Messages
4
Reaction score
0
Here is a bonus question that I was given yesterday. I am completely at a loss of what to do. Any suggestions?

A conducting loop with a half circle of radius r=0.20m and 3 straight sections. The half circle lies in a uniform field B that is directed out of the page. The magnitude of B as a function of time is given by B(t) = 4.0t^2 + 2.0t + 3.0 where B is in Teslas and t is in seconds. An ideal battery with EMF E=2.0V is connected to the loop. The loop has a resistance of 2.0 Ohms.
a) Find the magnitude and direction of the EMF induced in the loop.

b) What is the current in the loop at t = 10 seconds?
 
Physics news on Phys.org
Moore65 said:
Here is a bonus question that I was given yesterday. I am completely at a loss of what to do. Any suggestions?

A conducting loop with a half circle of radius r=0.20m and 3 straight sections. The half circle lies in a uniform field B that is directed out of the page. The magnitude of B as a function of time is given by B(t) = 4.0t^2 + 2.0t + 3.0 where B is in Teslas and t is in seconds. An ideal battery with EMF E=2.0V is connected to the loop. The loop has a resistance of 2.0 Ohms.
a) Find the magnitude and direction of the EMF induced in the loop.

b) What is the current in the loop at t = 10 seconds?

just use the equation for induced emf: -dflux/dt.
flux = B(t)*area of half circle
add this emf as a function of time to the battery emf of 2.0V. I think you add, at least. they tell you the B field is directed out of the page, but they don't tell you which way the battery is connected... anyway, add 2 + (-dflux/dt) and this is your emf in the loop as a function of time. then use v = ir to calculate i(t).
 
Last edited:
But how do I find the direction of the EMF?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top