Calculating Ion Charge (given Electron Configuration)

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Discussion Overview

The discussion revolves around calculating the ionic charge of transition metals, specifically using iron as an example. Participants explore the relationship between electron configurations and ionic charges, addressing the complexities involved in determining oxidation states and the factors influencing them.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that iron has an electronic configuration of 1s22s22p63s23p63d8 and questions how to calculate its ionic charge, which can be 2+ or 3+.
  • Another participant corrects the electronic configuration of neutral iron to 1s22s22p63s23p64s23d6, suggesting that the 4s orbital fills before the 3d orbital.
  • There is a discussion about the stability of different oxidation states, with one participant stating that determining stable oxidation states is complex and often based on experience rather than simple rules.
  • Participants express uncertainty about the randomness of oxidation states, noting that while some elements like manganese can form certain oxidation states, iron does not typically lose five electrons.
  • Questions arise regarding the factors that determine whether Fe(II) or Fe(III) will form, with a participant indicating a desire to research the various effects involved.
  • There is curiosity about the process of ionization, specifically which electron is affected and whether an electron can move between orbitals upon absorbing energy.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to calculate ionic charges or the factors influencing oxidation states, indicating multiple competing views and unresolved questions.

Contextual Notes

The discussion highlights limitations in understanding the complexities of electron configurations and oxidation states, as well as the dependence on various quantum mechanical effects that are not fully explored.

Who May Find This Useful

This discussion may be of interest to students studying chemistry or physics, particularly those focusing on transition metals and their properties, as well as educators looking for insights into common misconceptions about ionic charges.

FeDeX_LaTeX
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Hello;

My physics teacher told me that there was a way to calculate the ionic charge of a transition metal given its electronic configuration, but he did not tell me how, because it is 'too complicated'. I can't find any useful webpages on the subject, either... my teacher said that the subject was "too A-level" and that I don't need to know...

I will use an example. We can figure out that iron has an electronic configuration of 1s22s22p63s23p63d8. However, it has an ionic charge of 2+ (and sometimes 3+... why can it be either?). My question is, given this piece of information, how can one calculate iron's ionic charge? Or do you need more information?

Thanks.
 
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FeDeX_LaTeX said:
I will use an example. We can figure out that iron has an electronic configuration of 1s22s22p63s23p63d8. However, it has an ionic charge of 2+ (and sometimes 3+... why can it be either?). My question is, given this piece of information, how can one calculate iron's ionic charge? Or do you need more information?

Well, actually (neutral) iron should be:
1s22s22p63s23p64s23d6 (or in short [Ar]4s23d6).
See, 4s fills up before 3d.

I think what you're asking is 'How do you know which oxidation states are stable'?
Well the short answer is: Experience.
A bit more would be to say that it's very difficult because there are very many different effects involved here, mostly coming from quantum-mechanics (and in some cases, special relativity as well). If there was some kind of simple rule for it, we'd be teaching it. Of course, some rules you learn, such as noble gas configurations being are stable, mostly hold true.

So it basically appears to be very random. Manganese will happily form a Mn(V), but Iron will practically never lose 5 electrons, even though it has one more than Manganese!
 
Last edited:
Hello;

Thanks! Okay, so the sub-orbitals are filled in a set order? Okay, I understand. Is there a pattern? I think I remember seeing an illustration depicting the order of the different sub-orbitals.

So it appears to be random? Okay... so what determines if, say, whether or not Fe(II) or Fe(III) will be formed? I will try to research some of these 'different effects' you describe, there must be some good e-books around.

Also... if ionization occurs, on, say, a neutral iron atom, how do we know which electron is affected? If an electron absorbs a photon and is raised to a higher energy level, does that mean that, for example, an electron may move from 4s to 3d?

Cheers
 
FeDeX_LaTeX said:
so the sub-orbitals are filled in a set order? Okay, I understand. Is there a pattern?

Google aufbau principle.
 

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