Calculating Kinetic Energy and Speed with Rolling Hoop Problem

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The discussion revolves around calculating the kinetic energy and speed of a hoop rolling up a hill. The problem states that the hoop rolls at a constant velocity of 4 m/s and ascends a height of 0.8 m. Participants express confusion over how to solve the problem without specific mass or radius values, suggesting that arbitrary values can be used for calculations. The key equations for total kinetic energy, translational kinetic energy, and rotational kinetic energy are highlighted. The provided answers indicate that 50% of the initial total kinetic energy is due to rotational kinetic energy, and the speed at the top of the hill is 2.86 m/s.
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Homework Statement



A hoop, rolling at a constant velocity of 4m/s, rolls up a hill .8 m tall on to flat surface .
a) what percent of its initial total K.E. ( before rolling up the
hill) is due to rotational K.E.
b) how fast is it moving on top of hill.

Homework Equations


i=mr2
w=vr


The Attempt at a Solution


i am completely stumped, every equation i can find either requires a mass or a R or both. This problem looks like it should be easy that's why i feel so dumb for not knowing it.
 
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Just call the mass 'm' and the radius 'R'. You don't need actual values to answer the questions.
 
well my study guide gave me the answers a)50 % b) 2.86. and i don't understand at all how they got that.
 
The plot deepens from that of the last problem--(man you guys are trying to bite off a lot at one time this w/e):

KE(total)=KE(translational)+KE(rotational)

KE(rotational)=1/2 I*w^2
KE(translational)=1/2 m V^2

now just pick an arbitrary R and m and put both equations in common terms; hint use w=vr and your other eqn I=mR^2. That should take care of probllem 1, but finish the other problem first. Mutitasking is good but not in physics!:smile:
 
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