Calculating Kinetic Energy & Average Force of a 1.35g Bullet

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The kinetic energy of a 1.35g bullet traveling at 270m/s is calculated to be approximately 49.21 J. To find the average force exerted on the bullet over a 35cm barrel, the correct formula involves using the work-energy principle, where work done equals force multiplied by distance. There is confusion regarding whether to divide by time or distance for calculating average force. Assuming no friction losses, the work done on the bullet should equal the change in its kinetic energy. A thorough understanding of these concepts is essential for accurate calculations.
Rawpcgamer
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Part 1.) 1.35g bullet leaves the barrel of the gun going 270m/s. What is its kinetic Energy?
-I converted 1.35 g to kg = 0.00135g
-I arrived with an answer of 49.2075 J

Part 2.) If the length of the barrel of the gun described above is 35cm, find the average force exerted on the bullet to move it the length of the barrel.



What I had attempted to do is Mass X Velocity/ 35 cm
-im not sure if that's the way to find avergae force, because other examples I've seen its divided by time.

thank you for looking at this for me
 
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You know the total energy is the kinetic energy right? The work done by a force is just force*distance.
 
im sorry, i understand what your saying but i need an thorough explanation
 
Rawpcgamer said:
im sorry, i understand what your saying but i need an thorough explanation

If you assume no losses due to friction, then by conservation of mechanical energy, shouldn't the work done = change in kinetic energy?
 

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