Calculating Kinetic Energy of Meteor

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SUMMARY

The kinetic energy (KE) of a 1g (0.001kg) meteor traveling at 30,000 m/s is calculated using the formula KE = 1/2 MV^2, resulting in 450,000 Joules. The calculation confirms that the mass does not need to be multiplied by 4 when velocity is squared; the one-half term is independent of the squared velocity. This clarification addresses common misconceptions regarding the relationship between mass and velocity in kinetic energy calculations.

PREREQUISITES
  • Understanding of kinetic energy formula (KE = 1/2 MV^2)
  • Basic knowledge of units of mass (kilograms) and velocity (meters per second)
  • Familiarity with the concept of Joules as a unit of energy
  • Ability to perform basic arithmetic operations including squaring numbers
NEXT STEPS
  • Study the derivation of the kinetic energy formula in classical mechanics
  • Explore the implications of kinetic energy in different contexts, such as astrophysics
  • Learn about energy conservation and its applications in real-world scenarios
  • Investigate the differences between kinetic and potential energy
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding energy calculations in motion.

vandorin
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Homework Statement



What is the Kineti energy of a 1g (0.001kg) meteor traveling at 30,000m/s? Express your answer in Joules.

Homework Equations


KE=1/2MV^2


The Attempt at a Solution


1/2(.001kg)(30,000)^2 = 450000J


Now since 30,000 is squared, would i have to multiply .001kg by 4, before i did all of this math?
 
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Nope. You just plug .001kg in for M. Out of curiosity, why would you multiply by 4?
 
I thought that since v is squared, you had to multiply the mass by 4...or is that only if its 2v^2?
 
vandorin said:
I thought that since v is squared, you had to multiply the mass by 4...or is that only if its 2v^2?

Nope, the one half is a separate term from the squared term:

KE = (1/2) * (m) * (v2)
 

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