Calculating Magnetic Flux in a Toroidal Inductor

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    Flux Inductor
AI Thread Summary
To calculate the magnetic flux through each coil of a 4.50 mH toroidal inductor with 125 coils carrying a current of 11.5 A, the formula used is φ = L * I. Initially, the user mistakenly divided the inductance by the current, resulting in an incorrect value. Upon realizing the error, the correct calculation involves multiplying the inductance (0.0045 H) by the current (11.5 A), leading to the correct magnetic flux. The final value of magnetic flux per coil is derived by dividing the total flux by the number of coils. The discussion highlights the importance of using the correct formula for calculating magnetic flux in inductors.
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Homework Statement



A 4.50 mH toroidal inductor has 125 identical equally spaced coils.

4.5 mH = .0045 H (Wb/A)
N = 125
I = 11.5 A
φ = ? - this is what we're finding

If it carries an 11.5 A current, how much magnetic flux passes through each of its coils?

Homework Equations


I'm really blank on this one. I know that the units for the magnetic flux, φ, will be in units Wb. My educated guess is that the equation will be φ = inductance/current.

The Attempt at a Solution



φ = (.0045 H)/(11.5 A) = 3.91*10^-4 Wb
I divided that by 125 and got 3.13*10^-6 Wb
 
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Ah shi. How dumb of me. Just after posting I realized that I should multiply the inductance by the current and got the correct answer.
 
nvm, got it.
 
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