Calculating Magnetic Flux Needed for Ion Control

AI Thread Summary
To determine the required magnetic flux density for controlling negative ions with a mass of 277 u in a magnetic field, the velocity of the ions must first be calculated after being accelerated by a voltage of 3.0 kV. The relevant equations involve the relationship between kinetic energy and voltage, specifically using the formula QU = MV^2 / r and QVB = MV^2 / r. The challenge lies in finding the velocity (v) of the ions, which can be derived from the energy gained due to the acceleration. Once v is established, the magnetic flux density can be calculated to ensure the ions follow the desired circular path. The discussion emphasizes the need for clarity on the variables involved in the calculations.
tankarish
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Homework Statement


A magnet is used to control negative ions and only allow those with a specific mass to pass through a narrow gap opening . The magnet will bend the ion beam in a quarter circle of radius 50 cm .
In an experiment, a negative ion accelerated by a voltage of 3.0 kV.

Which magnetic flux density must the magnets have for these molecules with mass 277 u to follow the circular path through the magnet and get through the gap opening ?

Homework Equations


QU = MV ^ 2 * 1 / r , then mv ^ 2 * 1 / r = QVB

The Attempt at a Solution


Because we have volt , I think QU = MV ^ 2 * 1 / r , then mv ^ 2 * 1 / r = QVB
But we do not have Q, or v. Thus I do not know how I solve this .

Sorry for the English, but it seems the problem can't be solved?
 
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tankarish said:
QU = MV ^ 2 * 1 / r
I'm not sure what equation you are using here. What is U?

tankarish said:
But we do not have Q, or v.
You do not need Q to solve this question. You do, however, need v. This v would be the velocity of the negative ions after being accelerated by the voltage of 3kV, right before they enter the magnetic field. Can you find what is this v using the concept of energy?
Show us your working
 
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