Calculating Magnetic Moment of Rotating Charge

AI Thread Summary
To calculate the magnetic moment of a rotating charge, the relevant equation is M = IS, where I is the current and S is the area. The current I can be expressed as I = qf, with f being the frequency of rotation. The relationship between angular velocity (omega) and frequency is omega = 2πf, allowing for the substitution of f in the equation. The final expression for the magnetic moment becomes M = q(omega/2)(r^2). This approach simplifies the calculation by eliminating the need for radius when determining frequency.
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Homework Statement


A particle of charge q is rotating in a circular orbit of radius r with angular velocity omega. determine the magnetic moment associated with the motion of the charge


Homework Equations


M=IS



The Attempt at a Solution


M=I*(pi*r^2)
hav no idea how to get rid of the 'I' in the equation tho. its an 8 mark question so mayb it involvs something complicated

thanks in advance
 
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for a rotating charged particle, current I = q.f, where, q = charge, f = frequency of rotation.
 
you have r and omega, so you can find f.
 
why do i need r to find f? isn't omega just 2 pi f?
 
yes right. you don't need r. so did you get the answer?
 
M=qf*(pi*r^2)
M=q(omega/2pi)*(pi*r^2)
M=q(omega/2)*(r^2)
?
 
right.
 
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