Calculating magnetic susceptibility from the g factor

rwooduk
Messages
757
Reaction score
59
revision

already calculated J to be 15/2
have already found g to be 1.33

M = ngμJ



magnetic suseptibilty is 5X10^-7 m^3/mol

please could omeone tell me if it is possible to calculate the magnetic susceptibility from the above information? thanks in advance for an pointers.
 
Physics news on Phys.org
ok I've found μeff = gμ(J(J+1))^.5

and susceptibility = nμ(μeff)^2 / ?

is ? = KT

where would i find this formula,
 
edit yes its susceptibility = nμ(μeff)^2 / kT

admins please feel free to delete this thread
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top