Calculating Mass Flow Rate of Nitrogen at 0.3m^3/s

AI Thread Summary
To calculate the mass flow rate of nitrogen at a volumetric flow rate of 0.3 m³/s, given a pressure of 1 bar and a temperature of 18°C, the ideal gas law can be applied. The density of nitrogen can be derived using the equation ρ = nRT/P, where n is the number of moles. The number of moles can be calculated from the mass of the gas divided by its molecular mass, but the mass needs to be determined first. The flow area is not necessary for the calculation since the volumetric flow rate is already provided. Understanding these relationships allows for the accurate calculation of mass flow rate without needing additional parameters.
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Homework Statement



Work out the mass flow rate of Nitrogen traveling through a at 0.3m^3/s if the pressure is 1 bar and the temperature is 18°C and the ideal gas constant is 8314 J/Kg K

Homework Equations



m=ρ*V*A

m = mass flow rate
ρ= density
V = velocity
A = flow area

PV = nRT

where
P = pressure
V = volume
n = number of moles of gas
R = gas constant
T = absolute temperature


The Attempt at a Solution



I'm going round and round in a circle with it, the formula is simple enough and I know how to re-arrange it to get density but I need to work out the volume which is:

V = nRT/P

in order to do this I need to find the number of moles which is:

mass of the gas/ molecular mass

how do I work out the mass of the gas?

and how do I work out the flow area when there isn't one provided?

Thanks
 
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You are given the volumetric flow rate in m^3/s which is given by:

Volumetric flow rate = velocity * flow area.

Using this, you will not need the area
 
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