Calculating Mass of a Long Thin Rod

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SUMMARY

The discussion focuses on calculating the mass and center of mass of a long thin rod with a variable mass per unit length defined by the equation l = l0 (1 + 1.110x²), where l0 is 0.500 kg/m and L is 0.750 m. The correct mass of the rod, after integrating over its length, is determined to be 0.453 kg. Participants emphasize the necessity of integration to find both the total mass and the x-coordinate of the center of mass, highlighting the importance of applying calculus in this context.

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Homework Statement


A long thin rod lies along the x-axis from the origin to x=L, with L= 0.750 m. The mass per unit length, l (in kg/m) varies according to the equation l = l0 (1+1.110x2). The value of l0 is 0.500 kg/m and x is in meters.


Homework Equations


stated in equation


The Attempt at a Solution


I am lost on this question, i tried plugging the given numbers into the above equation, but my answer is not right(and tbh that seemed entirely to easy)

so i know .50*(1+1.110*.750^2) is not right, but other then that i am stuck, any help is greatly appreciated
 
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You need to integrate over the entire length of the rod.
 
alright i solved for the mass and got .453 kg, which is correct.

Now i need to figure out

Calculate the x-coordinate of the center of mass of the rod.
A=


I tried integrating x*m then dividing by m, but that didnt work
 

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