Calculating Mass Percent in UO2 Nuclear Fuel

AI Thread Summary
The discussion focuses on calculating mass percent in UO2 nuclear fuel, specifically how to determine the mass percentages of U-234, U-238, and O2 given a 3.5 percent enrichment of U-235. It highlights the confusion between atom percent and mass percent, noting that while oxygen constitutes about 66.7% of the atoms in UO2, it only accounts for approximately 12% of the mass. Participants suggest calculating the average mass of uranium and oxygen to derive the mass percent of the compound. The conversation emphasizes the importance of distinguishing between atomic and mass fractions in these calculations. Ultimately, clarity on these concepts is essential for accurate material definition in nuclear fuel simulations.
Goldberg
Messages
10
Reaction score
0

Homework Statement


Hello guys, I was using mcnp code SERPENT, and while defining materials i encountered a problem. The problem is that for example: if I'm given that i have a 3.5 percent enriched U-235. how do i find the rest of the mass percents of U-234, U-238, O2. Now since i know mass percent of U-235 i can use the equation given below to calculate the mass percent of U-234 in Uranium of that UO2 fuel, and the rest of the uranium would be U-238. But now what would be the weight percent of the Uranium in UO2 fuel?
From research i have found that O2 should be around 66 percent. but i have no way to calculate it. Can you please help. Thank you.

Homework Equations


25zjam9.jpg


The Attempt at a Solution

 
Physics news on Phys.org
You can calculate the average mass of an uranium atom with your isotopic mixture. You can look up the average mass of an oxygen atom. With both, you can calculate the average mass of the UO2 group, that should help to get the final answer.
 
mfb said:
You can calculate the average mass of an uranium atom with your isotopic mixture. You can look up the average mass of an oxygen atom. With both, you can calculate the average mass of the UO2 group, that should help to get the final answer.
I got that what do i do after that
 
After getting the final answer?

Can you show what you got?
 
mfb said:
After getting the final answer?

Can you show what you got?
The thing is that since its UO2, somehow in the answer I am given, U and O and O are divivded out of 100. So O2 is equal to ~66 percent. and as i increase the U-235 content Uranium mass percent increases from the basic ~33.33 percent, and the penalty of that is received by O2 mass percent.
The method you told me to calculate from gives me Uranium of UO2 as ~88 mass percent of the compound which is incorrect. It has to be about 66 percent.
 

Attachments

  • 20170228_094250.jpg
    20170228_094250.jpg
    40.5 KB · Views: 801
Goldberg said:
The thing is that since its UO2, somehow in the answer I am given, U and O and O are divivded out of 100. So O2 is equal to ~66 percent. and as i increase the U-235 content Uranium mass percent increases from the basic ~33.33 percent, and the penalty of that is received by O2 mass percent.
I don't understand that part.

Oxygen has 67% of the atoms, but its mass fraction is much smaller.
Uranium has about 88% of the mass fraction of UO2, the other 12% are oxygen.
 
mfb said:
I don't understand that part.

Oxygen has 67% of the atoms, but its mass fraction is much smaller.
Uranium has about 88% of the mass fraction of UO2, the other 12% are oxygen.
ok let's try to find the atom percent because the answer is given as ~66 percent oxygen, so that might be an option. because it's definitely not 88 % one.
So how do i get that?
 
UO2 - two out of three atoms are oxygen. 2/3 or 66.7%.
 
mfb said:
UO2 - two out of three atoms are oxygen. 2/3 or 66.7%.
I tried but wasnt able to do it . This is basically the table i want. if i take the number density of O2 and divide by the total i get 66 %. so basically i can either get the number density or this percentage.http://imgur.com/a/2M4HH
 
  • #10
Picture
 

Attachments

  • Untitled.png
    Untitled.png
    95.1 KB · Views: 713
  • #11
I don't understand the problem.

By number of atoms, you have 66.7% oxygen, the result of a trivial calculation as shown above.
By mass, you have 12% oxygen, the result of the calculation you did above.
Those two numbers are not expected to be the same.

Where is the problem now?
 
  • #12
Ok, The manual for this software is stupid. I know that the table is right so it might be from the number of atoms. Can you tell me how would i go about doing that
 
Back
Top