Calculating Maximum Magnetic Force on Electrons in a Television Set

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Homework Help Overview

The problem involves calculating the maximum magnetic force experienced by electrons in a television set after being accelerated through a potential difference of 23 kV and then passing through a magnetic field of 0.27 T.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between kinetic energy and potential difference, questioning the application of the energy equation. There are concerns about unit consistency and the implications of high velocity calculations, particularly in relation to the speed of light.

Discussion Status

Some participants have provided guidance on the interpretation of the energy equation and highlighted the importance of unit consistency. There is acknowledgment of errors in initial calculations, and one participant indicates they have arrived at the correct answer after further reflection.

Contextual Notes

Participants are navigating through the implications of using large values in calculations and the constraints of physical limits, such as the speed of light, in their reasoning.

thompson.1674
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magnetic force help ?

Homework Statement



In a television set, electrons are accelerated from rest through a potential difference of 23 kV. The electrons then pass through a 0.27 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.



Homework Equations



.5mv^2
qvbsin=F

The Attempt at a Solution


So this is what i have done but its not right:
23000=.5(9.11E-31)V^2
V=2.247E17
(1.6E-19)(2.247E17)(.27)=.00968 N

But is is not correct.
Can anyone help me out?
 
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Kinetic energy=pd*charge of electron.
 


Hi thompson,

thompson.1674 said:

Homework Statement



In a television set, electrons are accelerated from rest through a potential difference of 23 kV. The electrons then pass through a 0.27 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.



Homework Equations



.5mv^2
qvbsin=F

The Attempt at a Solution


So this is what i have done but its not right:
23000=.5(9.11E-31)V^2

I don't believe this is correct. For the energy equation, you'll need the potential energy change on the left; do you see what you have instead? Notice that it does not have the right units.

V=2.247E17
The upper limit on the possible speed would be the speed of light in a vacuum, which is a bit under 3E8 m/s, and so right away you know that can't be correct. That's an important thing to keep in mind when you do problems that involve these huge numbers.

(1.6E-19)(2.247E17)(.27)=.00968 N

But is is not correct.
Can anyone help me out?
 


okay i see what i did and i have the right answer. thanks for your help
 

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