Calculating Maximum Magnetic Force on Electrons in a Television Set

AI Thread Summary
Electrons in a television set are accelerated through a potential difference of 23 kV before entering a 0.27 T magnetic field. The maximum magnetic force on the electrons can be calculated using the equations for kinetic energy and magnetic force. Initial calculations were incorrect due to misinterpretation of energy units and an unrealistic speed estimation. The correct approach involves ensuring the energy calculations align with the physical limits of electron speed. Ultimately, the user resolved the confusion and found the correct answer with assistance.
thompson.1674
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magnetic force help ?

Homework Statement



In a television set, electrons are accelerated from rest through a potential difference of 23 kV. The electrons then pass through a 0.27 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.



Homework Equations



.5mv^2
qvbsin=F

The Attempt at a Solution


So this is what i have done but its not right:
23000=.5(9.11E-31)V^2
V=2.247E17
(1.6E-19)(2.247E17)(.27)=.00968 N

But is is not correct.
Can anyone help me out?
 
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Kinetic energy=pd*charge of electron.
 


Hi thompson,

thompson.1674 said:

Homework Statement



In a television set, electrons are accelerated from rest through a potential difference of 23 kV. The electrons then pass through a 0.27 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.



Homework Equations



.5mv^2
qvbsin=F

The Attempt at a Solution


So this is what i have done but its not right:
23000=.5(9.11E-31)V^2

I don't believe this is correct. For the energy equation, you'll need the potential energy change on the left; do you see what you have instead? Notice that it does not have the right units.

V=2.247E17
The upper limit on the possible speed would be the speed of light in a vacuum, which is a bit under 3E8 m/s, and so right away you know that can't be correct. That's an important thing to keep in mind when you do problems that involve these huge numbers.

(1.6E-19)(2.247E17)(.27)=.00968 N

But is is not correct.
Can anyone help me out?
 


okay i see what i did and i have the right answer. thanks for your help
 
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