Calculating Maximum Speed of a 65.0- fish on an Ideal Spring

AI Thread Summary
To calculate the maximum speed of a 65.0 kg fish hanging from a spring with a spring constant of 5310 N/m, the problem involves understanding the dynamics of vertical simple harmonic motion (SHM). The fish stretches the spring by 0.120 m, indicating the maximum displacement from the equilibrium position. The maximum speed can be determined using the formula v_max = ωA, where ω is the angular frequency and A is the amplitude of the motion. The angular frequency can be calculated from the spring constant and the mass of the fish. Properly identifying the equilibrium position is crucial for solving the problem accurately.
senoltreble
Messages
2
Reaction score
0

Homework Statement



A proud deep-sea fisherman hangs a 65.0- fish from an ideal spring having negligible mass. The fish stretches the spring 0.120 . k= 5310N/m

Im suppose to find the maximum speed it will reach.

Homework Equations





The Attempt at a Solution



I heard that velocity of vertical SHM can be found by wA, but i don't know what w is. So I am having hard time solving this question.
 
Physics news on Phys.org
I don't understand what this problem is asking.

A proud deep-sea fisherman hangs a 65.0- fish from an ideal spring having negligible mass. The fish stretches the spring 0.120 . k= 5310N/m

As I read this, it seems that the fish is in its equilibrium position and is therefore static.

...
 
senoltreble said:
k= 5310N/m
Is the spring constant given or did you calculate it?
 
What is the maximum speed it will reach? is the question. I found the spring constant, but i don't know if it helps solving the question
 
senoltreble said:
What is the maximum speed it will reach? is the question.
I understand the question. :wink:

I found the spring constant, but i don't know if it helps solving the question
You think you found the spring constant, but you made an error. The distance given is the maximum stretch of the spring from its unstretched position. So where's the new equilibrium point? Use that to find the correct value of the spring constant.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top