Calculating Minimum Diameter for Iron Bolt to Withstand Shear Forces

AI Thread Summary
To calculate the minimum diameter of an iron bolt that can withstand shear forces of 3200 N with a safety factor of 6.0, the shear strength of the material, which is 170 x 10^6 N/m², must be considered. The formula used is F/A, where F is the shear force and A is the cross-sectional area of the bolt. The area can be expressed in terms of the diameter (d) using the formula A = π(d/2)². By rearranging the equation and incorporating the safety factor, the minimum diameter can be determined. Understanding these calculations is essential for ensuring the bolt's integrity under shear loads.
pnl0628
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I need help getting started on this.
Question:
An iron bolt is used to connect two iron plates together. The bolt must withstand shear forces up to about 3200 N. Calculate the minimum diameter for the bolt, based on a saftey factor of 6.0.
Here is what I know so far.
Shear Strength is 170 x10^6
F/A
I don't even know where to start? Do I need a mass?
 
Last edited:
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Well, what have you done?. Remember the bolt is in simple shear (it cuts in 1 plane)
 
I don't understad what you just said. I'm not good with physics at all. Can you explain that to me please.
 
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