Calculating Minimum Stopping Distance for a Car: Solving for Vf^2 = Vo^2 + 2ad

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The minimum stopping distance for a car traveling at speed v can be calculated using the formula v^2 / (2 * coefficient of friction * g), where the coefficient of friction represents the interaction between the tires and the road, and g is the acceleration due to gravity. The equation Vf^2 = Vo^2 + 2ad can be rearranged to derive this stopping distance, with acceleration a defined as the coefficient of friction multiplied by g. The discussion confirms that the problem is straightforward and emphasizes the simplicity of the calculations involved. Overall, understanding the relationship between speed, friction, and stopping distance is crucial for safe driving.
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1. Show that the minimum stopping distance for a car traveling at speed v is equal to v^2 / 2*coefficient of friction*g, where the coefficient of static friction is between tires and the road and g is acceleration due to gravity.

I can re-arrange the equation Vf^2 = Vo^2 + 2ad to look the same as the above equation, since a = *coefficient of friction*g

Is that all this question is asking for? seems like I'm missing something here

thanks.
 
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Yep, sounds about right to me.
 
Unbelivebly,some problems are really that simple.:wink: I'm sure u'll get worse.:-p

Daniel.
 

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