Calculating Molar Concentration of Diluted HCl Solution

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In summary, the molar concentration of the diluted hydrochloric acid is 0.60 M. This was determined by using the formula c1v1=c2v2, where c1 and v1 represent the initial concentration and volume, and c2 and v2 represent the final concentration and volume. The total volume of the solution is 500 mL and the initial concentration is 12 M. Therefore, the final concentration is 0.60 M. The answer given in the book may be incorrect, as it does not match the calculated value.
  • #1
fish
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If 25 mL of 12 M HCl are added to 475 mL of distilled water, what is the molar concentration of the diluted hydrochloric acid?

c1v1=c2v2
25*12=475c
c=.63 M HCL

book has the answer as .60 M HCL
Isn't the answer .63?
 
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  • #2
"25*12=475c"

Think about this a moment; you've asserted something different from the problem statement, "25 mL of 12 M HCl are added to 475 mL ---."
 
  • #3
Your total volume is 500ml, and you have 12 moles. 12moles/.500L is?
 
  • #4
this seems to work, .30 mol/.500L = .60 M
 
  • #5
Originally posted by GeneralChemTutor
Your total volume is 500ml, and you have 12 moles. 12moles/.500L is?

No u have 12/40=0.3 moles
and now volume is 500mL

therefore molarity= 0.3*2=0.60

it is right way fish
 
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