Calculating Molar Mass of an Unknown Gas from Effusion Rate

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To determine the molar mass of an unknown gas based on its effusion rate compared to methane (CH4), the relationship between effusion rates and molar mass is utilized. The rate of effusion of the unknown gas is 24.0 mL/min, while methane's rate is 47.8 mL/min. Since effusion rates are inversely proportional to molar mass, a lower effusion rate indicates a higher molar mass. The molar mass of methane is calculated as 16 g/mol (C: 12 g/mol + H: 1 g/mol x 4). Using Graham's law of effusion, the molar mass of the unknown gas can be calculated by setting up a ratio based on the effusion rates. This approach allows for the determination of the unknown gas's molar mass, confirming that it is greater than that of methane.
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effusion rates...please help!

Could someone please explain to me how to do this question...
The rate of effusion of a particular gas was measured to be 24.0 mL/min. Under the same conditions the rate of effusion of pure methane gas, (CH4) is 47.8 mL/min. What is the molar mass of the unknown gas?
 
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Effusion rates are indirectly proportional with the molar mass; if the molecule is bigger, it can't move fast. So the particular gas has a greater molar mass.

Calculate methane's molar mass by taking C:12, and H:1 grams/mol, and find the unknown gas' molar mass.

Regards,
chem_tr
 
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