Calculating Momentum & Angular Momentum in a Magnetic Field

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A particle with a charge of 4.5E-19 C is in a circular orbit of radius 0.465 m within a magnetic field of 1.7 T. The linear momentum was calculated to be 3.6E-19 kg*m/s using the equation R=(mv)/(qB). However, the user struggles to find the angular momentum since they only have the product of mass and velocity (mv) and not their individual values. The relationship for angular momentum is given as L = mvr, but without knowing mass or velocity separately, the calculation remains unclear. Further assistance is requested to resolve the angular momentum calculation.
eku_girl83
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Here's my problem:

A particle with charge 4.5E-19 C travels in a circular orbit with radius .465 m due to the force exerted on it by a magnetic field with magnitude 1.7 T and perpendicular to the orbit.

a) What is the magnitude of the momentum p of the particle?
I used the equation R=(mv)/(qB) and calculated mv (linear momentum) to be 3.6E-19 kg*m/s.

b) What is the magnitude of the angular momentum L of the particle?
Herein lies the rub! Angular momentum = v/R = qB/m
I don't know velocity or mass independently, only their product (mv). So how do I calculate angular momentum?

Thanks for any help!
 
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Double-posting is annoying.
 
Angular momentum of a particle moving in a circular motion about the centre is : mvr = pR
 
a) Only God knows

b) The hell would I know
 

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