Calculating net gravitational force on the moon

AI Thread Summary
The discussion focuses on calculating the net gravitational force on the moon due to the sun and earth. The user initially calculated the gravitational forces as 4.04x10^20 N from the sun and 1.97x10^20 N from the earth, leading to a net force of 4.49x10^20 N. However, they were informed that they used an incorrect distance for the sun-moon calculation, which affected their results. After correcting the distance, the user successfully arrived at the correct answer. The conversation emphasizes the importance of accurate distance values in gravitational force calculations.
rymath
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Homework Statement



The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force vector F SM that the sun exerts on the moon is perpendicular to the force vector F EM that the Earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of Earth = 5.98 1024 kg, mass of moon = 7.35 1022 kg. The distances shown in the drawing are rSM = 1.5 1011 m and rEM = 3.85 108 m. Determine the magnitude of the net gravitational force on the moon.



Homework Equations


F=G m1m2/r^2
Fnet = √(F1^2 + F2^2)
G = 6.674x10^-11


The Attempt at a Solution


For the force between the Sun and the Moon I got 4.04x10^20 and for the force between the Earth and the Moon i got 1.97x10^20 N and then for the net force I got 4.49x10^20 N

I really don't know where I went wrong. I'm guessing my exponents are probably messed up? I've double and triple and quadruple checked it and I feel like my answer is right but WebAssign is saying I'm wrong. The calculations I used were

F(Sun and moon) = (6.674x10^-11(1.99x10^30 x 7.35x10^22)/(1.55x10^11)^2
Like I said, I got 4.04x10^20 N

F(Earth and moon) = (6.674x10^-11(5.94x10^24 x 7.35x10^22)/(3.85x10^8)^2
1.97x10^20 N

Fnet = √((4.04x10^20)^2 + (1.97x10^20)^2)

4.49x10^20 N

Thanks for any help!
 
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rymath said:

Homework Statement



The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force vector F SM that the sun exerts on the moon is perpendicular to the force vector F EM that the Earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of Earth = 5.98 1024 kg, mass of moon = 7.35 1022 kg. The distances shown in the drawing are rSM = 1.5 1011 m and rEM = 3.85 108 m. Determine the magnitude of the net gravitational force on the moon.



Homework Equations


F=G m1m2/r^2
Fnet = √(F1^2 + F2^2)
G = 6.674x10^-11


The Attempt at a Solution


For the force between the Sun and the Moon I got 4.04x10^20 and for the force between the Earth and the Moon i got 1.97x10^20 N and then for the net force I got 4.49x10^20 N

I really don't know where I went wrong. I'm guessing my exponents are probably messed up? I've double and triple and quadruple checked it and I feel like my answer is right but WebAssign is saying I'm wrong. The calculations I used were

F(Sun and moon) = (6.674x10^-11(1.99x10^30 x 7.35x10^22)/(1.55x10^11)^2
Like I said, I got 4.04x10^20 N

F(Earth and moon) = (6.674x10^-11(5.94x10^24 x 7.35x10^22)/(3.85x10^8)^2
1.97x10^20 N

Fnet = √((4.04x10^20)^2 + (1.97x10^20)^2)

4.49x10^20 N

Thanks for any help!
Welcome to PF!

It looks like you used a slightly wrong value for the Sun-Moon distance in your calculation. Other than that, things look pretty good -- you are on the right track and your answer is not that far off.
 
Redbelly98 said:
Welcome to PF!

It looks like you used a slightly wrong value for the Sun-Moon distance in your calculation. Other than that, things look pretty good -- you are on the right track and your answer is not that far off.

Thanks for pointing that out to me! I feel so dumb. Got the answer right!

Thank you so much :)
 
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