Calculating Normal Force and Acceleration in Dynamics Physics - Urgent Help

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To determine the normal force on a 1.0 kg water bottle being lifted with a force of 4.0 N, the gravitational force (Fg) acting on the bottle is calculated to be 9.8 N downwards. The net force can be found by subtracting the applied force from the gravitational force. This results in a normal force that is less than the weight of the bottle, indicating it is not fully lifted. The acceleration of the bottle can then be calculated using Newton's second law, taking into account the net force. Immediate assistance is requested to resolve these calculations.
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Homework Statement



Sara wonders what the normal force on her 1.0 kg water bottle would be if she tries to lift it with 4.0 N (she used a Newton spring scale to measure her applied force). What is the bottle's acceleration?


Homework Equations



Fg = mg


The Attempt at a Solution



I found Fg which is 9.8 N downwards.
Not sure what to do after this.
Any help, please?
 
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Can someone please help me right now?
 


This is urgent, please!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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