- #1

Naeem

- 194

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Q. What would the normal force be on the student at the top of the wheel if the wheel's velocity were doubled

If the wheels velocity were doubled mv^2 / R increases by a factor of four, i.e

Weight of the student = 75 kg * 9.81 = 735.75 N - Normal Force ( 556 N )

= 179.75 N * 4 ( coz, it increases by a factor of 4 )

= 719 N

There fore Normal force = 719 N - 735.75 N = 16.75 N , is this correct!