Calculating Per Unit Fault Impedance: Finding Errors in Given Relationships

AI Thread Summary
The discussion revolves around the calculation of per unit fault impedance and the validity of given relationships. Participants express confusion over the equation "Xohms = [ V / sqrt(3) ] * Ifault," with one asserting it is incorrect and suggesting it should be rearranged. Clarifications indicate that the equation may be a typo, proposing an alternative formulation. The conversation highlights the need for accurate algebraic representation in electrical calculations. Ultimately, the focus remains on resolving the discrepancies in the equations provided.
acw260
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Homework Statement


Given the relationships:

Xpu = MVAbase / MVAfault

Xpu = ( MVAbase / MVArated ) * ( X% / 100 )

MVAfault = sqrt(3) * V * Ifault

Xohms = [ V / sqrt(3) ] * Ifault

Homework Equations



Show that:

Xpu = [ MVAbase / V^2 ] * Xohms

The Attempt at a Solution



No matter how I approach this problem I keep finding that one of the given relationships must be incorrect. Could someone with better algebra skills then me please take a look and confirm whether (a) there is an error in the set problem or (b) I'm just being dense?

Thanks
 
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I have no idea of what you are trying to ask - but "Xohms = [ V / sqrt(3) ] * Ifault" seems very wrong. Resistance (ohms) is always Voltage divided by current.
 
Please see the attachment for the problem in its original format, which should make things clearer.

I have solved the derivation of equation 5(a).

I can solve the derivation of equation 5(b) no problem using "V=IX" (ignoring the resistance of the cables for the purposes of the fault calculation, as instructed in the problem).

What I can't see is how the given equation "Xohms = [ V / sqrt(3) ] * Ifault" fits into the derivation of equation 5(b). This equation seems wrong.
 

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acw260 said:
What I can't see is how the given equation "Xohms = [ V / sqrt(3) ] * Ifault" fits into the derivation of equation 5(b). This equation seems wrong.
A typo. It should be "Xohms = V /[sqrt(3) * Ifault]".
 
acw260 said:
Xohms = [ V / sqrt(3) ] * Ifault

Svein said:
A typo. It should be "Xohms = V /[sqrt(3) * Ifault]".

Or, equivalently, Xohms = [ V / sqrt(3) ] / Ifault
 
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