Calculating Phase Shift for a Series RC Circuit

AI Thread Summary
To calculate the phase shift in a series RC circuit with a resistor of 362 Ohms and a capacitor of 50.0 µF at a frequency of 11.7 Hz, the impedance is given as 452.836 Ohms. The relevant equations include the capacitive reactance (Xc = 1/(ωC)), where ω = 2πf, and the impedance formula (Z = √(R² + (Xc)²)). The phase angle is determined using the formula tan(θ) = (Xc)/R, leading to θ = tan⁻¹(Xc/R). Despite applying these equations, the calculated phase angle of 37 degrees was found to be incorrect, indicating a potential error in the calculations or assumptions made. Further review of the calculations is necessary to resolve the discrepancy.
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Homework Statement



A resistor of 362 Ohms is connected in series with a capacitor of 50.0 µF capacitance. A sinusoidal signal of f = 11.7 Hz experiences an impedance of 452.836 Ohms. Find the phase shift between the current and voltage at f = 11.7 Hz.

Homework Equations



I tried using the equation tan = (Xc)/R

Xc=1/(wC)

w=2(pi)f

Z=sqrt(R^2+(Xc)^2)
 
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Where are you stuck exactly?
 
Well, I used all four of those equations (specifically the first one b/c the question is asking for the angle), but when I plugged in my answer, it was wrong.

tan=(Xc)/R
theta=tan^-1(Xc/R)=37 degrees
 
Hmmm, let me read it again.
 

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