Calculating Refractive Index for Extraordinary Ray in Calcite Crystal

  • Thread starter Thread starter v_pino
  • Start date Start date
  • Tags Tags
    Law Snell's law
v_pino
Messages
156
Reaction score
0

Homework Statement


A beam of light travels through a calcite crystal such that its wave vector makes an angle of 30degrees with the optic axis. Calculate the refractive index experienced by the extraordinary ray if the relative dielectric constants for light polarized parallel and perpendicular to the optic axis are 2.208 and 2.749, respectively.


Homework Equations


Perhaps Snell's law? : n1 sin(theta1) = n2 sin(theta2)
Should I set it as Brewsters angle?

The Attempt at a Solution



I've also tried square-rooting 2.749 which gives me a similar answer to the actual solution.

The actual solution should be 1.61
 
Physics news on Phys.org
Could this be to do with total internal reflection in a polarizing beam-splitter?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top