Calculating Relay Resistance for 12V Circuit

AI Thread Summary
The discussion revolves around calculating the resistance of a relay in a 12V circuit where the relay activates at a current of 0.0048A. The user applies Ohm's Law, determining that the total resistance in the circuit must equal 2500 Ohms, leading to a calculated relay resistance of 1700 Ohms after accounting for the 800 Ohm resistor. There is uncertainty about whether the circuit is indeed designed to deliver the specified current of 0.0048A. Participants confirm that if the current through the coil reaches 0.0048A, the calculations are correct. The simplicity of the problem raises questions about its value in a typical homework context.
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Homework Statement



A relay switches on when the current through the coil reaches 0.0048A.

In a circuit, a battery of 12V is connected in series with this relay it switches on when another resistor of 800 Ohm is connected to it.

Calculate the resistance of the relay.

Homework Equations





The Attempt at a Solution



V= IR
12V = 0.0048A * (800 ohm + coil resistance)

12V / 0.0048A = 800 ohm + coil resistance

coil resistance = 2500 ohm - 800 ohm
=1700 ohm

However, I am not sure if I am on the right track...
 
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Is the circuit with the battery and the resistor supposed to deliver 0.0048A? If so, your solution is right.
 
ideasrule said:
Is the circuit with the battery and the resistor supposed to deliver 0.0048A? If so, your solution is right.

from the first line, "A relay switches on when the current through the coil reaches 0.0048A."

so can i conclude that the current passing through the coil has reached 0.0048A? which means that current in the circuit is 0.0048A

however, this question is worth 4 marks and it seems to easy for a usual 4 mark question...
 
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