Calculating Residue of cos(z)/z in Contour Integral

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SUMMARY

The discussion focuses on calculating the contour integral \(\oint \frac{\cos(z)}{z}\) around the circle defined by \(|z|=1.5\). The integral utilizes the Cauchy Integral Formula and the Residue Theorem, with the residue at the pole \(z=0\) being determined. The residue is confirmed to be 1, leading to the final result of the integral being \(2\pi i\). The user sought clarification on the residue calculation process, which involves evaluating \(\lim_{z \to 0} (z-0) \frac{\cos(z)}{z}\).

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Homework Statement


So the problem at hand is to calculate the contour integral \oint cos(z)/z around the circle abs(z)=1.5 .


Homework Equations


The integral is going to follow from the Cauchy-Integral Formula and the Residue theorem. The problem I am having is figuring out what the residue is going to be.


The Attempt at a Solution



So I know the pole is at z = 0, which lies inside of the contour. So the integral reduces to I=2*pi*i*residue @ 0. What I can't figure out is how to determine the residue. If I use maple, I know that the residue is 1, but I want to figure out where it comes from it. Any help?
 
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If f(z) has a simple pole at z=c then the residue is lim z->c of (z-c)*f(z), isn't it? What does that give you?
 
Ah, thank you. I just needed someone to write it out clearly for me.

So the formal answer =2*Pi*i
 
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