Calculating Resistance Problem: Equivalent Resistance Between Adjacent Vertices

  • Thread starter Thread starter prasum
  • Start date Start date
  • Tags Tags
    Resistance
prasum
Messages
8
Reaction score
0
Problem:
Each edge of a cube is built with a one ohm resistor. The body
diagonals are also built with one ohm resistor each. Find out the
equivalent resistance between any two adjacent vertices.

Iam not able to get this problem at all. Please help me. its urgent.

please help------------------
 
Physics news on Phys.org
This looks pretty time consuming, and I don't really have the time or motivation to work it out to be honest :), but I will tell you the general procedure for these types of things. You need to create nodal equations, see how they relate, and then solve. You'll have a large number of equations to piece together, double digits, but you should be able to catch on to some kind of series or clever way to combine them. It's just like getting the req for your basic parallel or series resistances, just on a larger scale.
 
can u please elaborate a little.give me some starting eqn or something so that i can start the problem. please help.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top