Calculating Slit Width from Monochromatic Light Diffraction | 616nm Wavelength

[inflames829]

Homework Statement

monochromatic light of wavelength 616nm is incident on a narrow slit. On a screen 1.7m away, the distance between the second diffraction minimum and the central maximum is 1.8cm. What is the width of the slit in mm?

Homework Equations

The Attempt at a Solution

For the question i use the formula lambda = y x w / L
where L is the length to screen, y is the distance between the middle of the bright spot and the first dark line and w is the slit width. I rearrange the equation to get w and then just pug in the values and I get w = lambda x L / Y and the answer i get is w = 616E-9 x 1.7 / 0.018 = 5.82E-5m, bbut this answer is incorrect, can someone please help me with whatim doing wrong

 

[Kurdt]

The question gives the distance to the second minimum not the first.

 

[Moetasim]

?Your approach and equation are correct, but there seems to be a mistake in your calculation. The correct answer should be w = 616E-9 x 1.7 / 0.018 = 0.057mm. Make sure to double check your calculations and units to ensure accuracy. Additionally, it is important to note that this calculation assumes that the slit is very narrow compared to the wavelength of light, so it may not be accurate for wider slits.