Calculating Speed on a 10m High Slope with a Starting Speed of 5.0 m/s

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Homework Help Overview

The problem involves a skier coasting down a 10m high slope, starting with an initial speed of 5.0 m/s. The discussion centers around calculating the skier's speed at the bottom of the slope, considering the effects of gravity and energy conservation principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy, questioning how to set up the problem and whether mass is necessary for the calculations. Some express difficulty in conceptualizing the problem despite its apparent simplicity.

Discussion Status

Participants are exploring the relationship between potential and kinetic energy, with one providing a clarification that mass cancels out in the energy equations. There is an indication of productive guidance being offered, as one participant expresses gratitude for the assistance.

Contextual Notes

One participant mentions struggling with the problem for an extended period, indicating a potential challenge in understanding the setup or application of the relevant equations.

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Homework Statement


A skier coasts down a very smooth, 10m high slope. If the speed of the skier on top of the slope is 5.0 m/s what's the speed at the bottom of the slope.


Homework Equations





The Attempt at a Solution



I have to take gravity into consideration right?
 
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I would use conservation of energy

KEi + PEi = KEf + PEf

Does that help?
 
I'm sorry but I can't seem to set this problem up, I have been doing this homework for 3 hours and this problem seems so easy. to Pe = mgy, but i have a brain fart on finding mass.
Kinetic - energy of Motion (1/2mv^2). can yo walk me through it please
 
You do not need the mass of the skier because it will cancel out of the equation.

1/2mvi^2 + mgy = 1/2mvf^2

The masses cancel out. You then have the initial velocity, the g, the y, and thus you should be able to solve for the final velocity. Now do you get it?
 
yes thank you
 

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