Calculating Stress Area at Hole Edge of Tube & Rod

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To calculate the stress area at the edge of a tube with a rod inserted and secured by a pin, consider both axial tensile stress and bearing stresses on the tube wall at the pin location. The axial tensile stress is determined by the tube's cross-sectional area, while the bearing stress is calculated by dividing the force on the wall at the pin by the product of the pin diameter and wall thickness. It's important to account for the non-uniform distribution of force, which is highest along the axis of the applied force and zero normal to it. Additionally, shear tearout at the hole should be evaluated, assuming the pin diameter is small compared to the tube diameter. Understanding these factors is crucial for accurate design and analysis.
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I have a tube with a rod inserted into it at a set depth. The rod is held in place by a round pin that passes through a hole in the side of the tube and into the rod. Assuming the pin and hole are the same diameter or very close, I'd like to know how to calculate the stress area on the edge of the tube when a force is applied to the end of the rod when the tube is anchored. I know that the force exerted by the pin is highest along the axis of the force and zero normal to it. So the force involved is not equal over the diameter of the pin which I'm puzzled about. Thanks for the help.
 
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Actual stress distribution is quite complex, but for purposes of design, analysis can be simplified. In addition to axial tensile stress, a function of the tube cross section area, there are bearing stresses on the wall at the pin, which is the force
on the wall at the pin divided by ( pin diameter *wall thickness). Also check shear tearout at the hole. Assumption is that pin diameter is small relative to tube diameter.
 
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