Calculating the Angular Size of an Image with a Magnifying Glass

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 9K views
kbray278
Messages
2
Reaction score
0

Homework Statement



The near point of a naked eye is 33 cm. When an object is placed at the near point and viewed by the naked eye, it has an angular size of 0.060 rad. A magnifying glass has a focal length of 16 cm, and is held next to the eye. The enlarged image that is seen is located 51 cm from the magnifying glass. Determine the angular size of the image.


Homework Equations


Angular size=Theta(i)/Theta(o)


The Attempt at a Solution



Wasn't sure what to do
 
on Phys.org
angular size of the object αo = h/33. The angular size is given. Find the linear size h of the object.
Focal length of the glass and the image distance from the magnifying glass is given. From that find the object distance so
The angular size of the image = h/so.
 
rl.bhat said:
angular size of the object αo = h/33. The angular size is given. Find the linear size h of the object.
Focal length of the glass and the image distance from the magnifying glass is given. From that find the object distance so
The angular size of the image = h/so.

To clarify, height of image/distance of image (which you want to find) = height of object/distance of object. This can easily be seen with a ray diagram.
 
ideasrule said:
To clarify, height of image/distance of image (which you want to find) = height of object/distance of object. This can easily be seen with a ray diagram.
In this problem size of the image is irrelevant. You have to bring the object closer to the eye to make its angular size larger to see its details clearly. Because of the limitation of the accommodation of the eye, we cannot see the object clearly. To see the object in the same position, we have to use magnifying glass which forms its image at near point.