Calculating the coefficient of kinetic friction

AI Thread Summary
The discussion revolves around calculating the coefficient of kinetic friction from a lab experiment involving a wooden block and a weight on a pulley. Key variables include the time taken for the block to travel a distance of 0.5 meters, the mass of the block (0.243 kg), and the mass of the weight (0.110 kg). Participants confirm that solving for acceleration is a valid approach to find the coefficient of kinetic friction, emphasizing the importance of correctly applying Newton's second law. There is a caution against simply using force from F=ma without considering other factors. The conversation highlights the need for careful calculations to ensure accurate results in determining the coefficient of kinetic friction.
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Homework Statement


This was a lab. We attached a weight to a pulley and connected it to a wooden block. the wooden block was placed on a wooden board on a table. we dropped the weight and calculated the time it to the block to travel a certain distance.We have the variables
T=1.28 s
Mass of wooden block=.243 kg
Mass of weight on pulley=.110 kg
d=.5 m

Homework Equations


D=vitf+1/2atf^2
F=ma
Force of kinetic friction=coefficient of kinetic friction times normal force

The Attempt at a Solution


I solved for acceleration and used that to solve for the coefficient. I'm sure that's wrong
 
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Your approach sounds ok to me. Provided you didn't just use F from F=MA.
 
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