Calculating the Cost of Heating with a Less Efficient Heat Pump

AI Thread Summary
The discussion centers on calculating heating costs using a less efficient heat pump compared to ideal electric heaters. The heat pump operates at a coefficient of performance (COP) that is 75% of the theoretical maximum, impacting cost calculations. Participants seek clarification on key variables, such as Qh (heat output) and W_in (input work), and how these relate to both heating methods. There is a focus on understanding the equations governing the heat pump's efficiency and the implications for overall heating expenses. The conversation emphasizes the need for precise calculations to determine the actual cost of heating with the heat pump.
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Homework Statement


Assume that you heat your home with a heat pump whose heat exchanger is at Tc=2∘C, and which maintains the baseboard radiators at Th=47∘C. If it would cost $1000 to heat the house for one winter with ideal electric heaters (which have a coefficient of performance of 1), how much would it cost if the actual coefficient of performance of the heat pump were 75% of that allowed by thermodynamics?

Homework Equations


Th/(Th-Tc)=K
U=W+Q
K=Qh/Win

The Attempt at a Solution


i converted to kelvin and then plugged the temperatures into the equation and set it equal to Qh/Win but i am unsure how to proceed. any help is greatly appreciated.
 
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It's best to type out your working so we can see exactly what you've done.

I assume 'K' is COP (Coefficient of performance), did you account for the given inefficiency here?

What does Qh represent? what are it's units? Is it the same for both the heater and the heat pump? How can you use that information?

What does W_in represent? what are it's units? Is it the same for both the heater and the heat pump? How can you use that information?
 
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