Calculating the Free Fall of Two Balls

AI Thread Summary
Two balls are dropped from a height of 5 meters, with gravity set at 10 m/s². The problem involves calculating the time it takes for the balls to fall, neglecting air resistance. The relevant equation for this scenario is y = 1/2at², where y is the height. After some confusion, the correct calculation leads to a fall time of approximately 1 second. The discussion highlights the importance of rest and clarity in solving physics problems.
Robdog
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Homework Statement



Two ball are dropped from 5m high, Use 10 m/s^2 for the magnitude of the acceleration due to gravity.


Homework Equations



How do i start?

The Attempt at a Solution



not sure on how to start so i haven't attempted:(
 
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the problem asks how much time is elapsed during the fall of the 5.0m at a rate of 10m/s^2

Im sure there is an equation for this but i don't know which one or where to find it...
 
Last edited:
If something starts at rest, i.e. with zero velocity, how far does is travel in time, t, if the acceleration is constant.

See - http://hyperphysics.phy-astr.gsu.edu/hbase/acons.html

The same concept applies for horizontal (x) or vertical (y) motion, provided the acceleration is constant.
 
so... y=1/2at^2... y equal to the hight of 5m? if so then i get 5m=1/2(10m/s^2)T^2 which = square root of 5.00s which = 2.24s? but the that answer is still wrong. What did i do wrong.
 
o nvm should be the square root of 1.00s... ill try that, wow i feel like an idiot... i need to sleep
 
Well - you figured it out. Do get some sleep, and refer to hyperphysics when the mind is more relaxed.
 
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