Calculating the Gauge of a Copper Wire for a Thermometer Bridge Circuit

AI Thread Summary
The discussion revolves around calculating the correct gauge of copper wire for a thermometer bridge circuit, with the user struggling to reconcile their calculated wire diameter with the SWG table values. They initially misinterpret the table, confusing resistance per unit length with resistivity, leading to incorrect assumptions about wire size. Clarifications indicate that the resistance of the thermometer at 20°C is given and should be used directly in calculations rather than recalculated. Additionally, the user is cautioned about the implications of exceeding the thermometer's maximum designed temperature of 200°C and the potential sources of additional resistance. Understanding these points is crucial for accurately determining the wire gauge needed for the circuit.
PaxFinnica96
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Homework Statement
a. The resistance thermometer bridge circuit shown in FIGURE 1 has a designed maximum temperature of 200°C, ignoring the effects of connecting wire resistance. If the connecting loop is 250 m determine the smallest gauge (swg) of copper wire which must be used if the indicated maximum temperature is to be less than 202°C.
The temperature coefficient of resistance of the thermometer is 0.0042 °C–1 and the resistance of the thermometer is 112 Ω at 20°C. Assume the connecting leads are at 20°C.
b. Using the gauge of copper wire calculated in part (a), calculate the maximum indicated temperature using a 3-wire system (as shown in FIGURE 2) over a distance of 125 m.
Relevant Equations
Rt = R0(1 + at)

R1RT = R2RS

R = pL/A = Resistance = (Resistivity) x Length of wire / cross-sectional area

A = (pi x d2) / 4

d = squareroot(4A /pi)
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Hi All,

Really struggling to get my head around what I'm doing wrong - every time my answer of wire diameter comes out too small for what's included in the table of SWG. I must be doing something wrong somewhere - my attempt is below.

Any help is very much appreciated.

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1 m = 103 mm
1 m2 = 106 mm2
4.22 x 10-8 m2 = ? mm2
 
kuruman said:
1 m = 103 mm
1 m2 = 106 mm2
4.22 x 10-8 m2 = ? mm2
Ah ok, but 4.22 x10^-8 m^2 = 0.0422 mm^2 however I cannot see this value of diameter in the SWG table provided - do you think it would be easier to calculate the ohm/m for copper instead or is there another error in my method?
 
PaxFinnica96 said:
Ah ok, but 4.22 x10^-8 m^2 = 0.0422 mm^2 however I cannot see this value of diameter in the SWG table provided - do you think it would be easier to calculate the ohm/m for copper instead or is there another error in my method?
1. You don't need to calculate ohm/m; it is given in the table you posted.
2. Can you explain how you think this bridge circuit is supposed to work? Specifically, how does this "fundamental interval" enter the picture?
 
Ok, well I believe the bridge is designed to be balanced so that the value of resistance, RS, can be calculated and thus related to the resistance (ant therefore temperature) of the thermometer. It is this value I have used to incorporate into my rearranged resistivity equation to determine the wire diameter. Am I right to use the fundamental interval of the thermometer to calculate the wire size of the connecting loop?
 
The question is more complex than simply calculating a diameter and looking it up.
First, you misunderstood the table. The numbers have units of Ohm/m. These are not resistivities but resistances per unit length for a given gauge. The dimensions of resistivity are Resistance times Length.
Secondly, the resistance of the thermometer is given as ##R_0=112~\Omega## at 20 oC. You should not have to recalculate it but should use it in the equation for the temperature dependence of the thermometer.
Thirdly, the question asks you to "determine the smallest gauge (swg) of copper wire which must be used if the indicated maximum temperature is to be less than 202°C." Why would a thermometer that has a maximum designed temperature of 200 oC give a reading of 202 oC? Stated differently, suppose you determined independently that the thermometer is at 200 oC, yet the bridge balances at a thermometer resistance appropriate to 202 oC, where did the extra resistance come from?
 
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