Calculating the Maximum Displacement of Kate's Bungee Jump

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cj3
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Homework Statement


Kate, a bungee jumper, wants to jump off the edge of a bridge that spans a river below. Kate has a mass (m) , and the surface of the bridge is a height (h) above the water. The bungee cord, which has length (L) when unstretched, will first straighten and then stretch as Kate falls.

Assume the following:

The bungee cord behaves as an ideal spring once it begins to stretch, with spring constant (k)
Kate doesn't actually jump but simply steps off the edge of the bridge and falls straight downward.
Kate's height is negligible compared to the length of the bungee cord. Hence, she can be treated as a point particle.

Use (g) for the magnitude of the acceleration due to gravity.


How far below the bridge will Kate eventually be hanging, once she stops oscillating and comes finally to rest? Assume that she doesn't touch the water.




Homework Equations


Fs=-kx
Ws=.5kx2
Ei=Ef


The Attempt at a Solution


i'm not really sure...i know i have to use conservation of energy so this is what i tried
.5kx2+.5mvi2+mgh1=.5mvf2+mgh2
.5kx2=.5mvf2+2mgL
x=sqrt(mvf2+2mgL)
 
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Hi cj3,

cj3 said:

Homework Statement


Kate, a bungee jumper, wants to jump off the edge of a bridge that spans a river below. Kate has a mass (m) , and the surface of the bridge is a height (h) above the water. The bungee cord, which has length (L) when unstretched, will first straighten and then stretch as Kate falls.

Assume the following:

The bungee cord behaves as an ideal spring once it begins to stretch, with spring constant (k)
Kate doesn't actually jump but simply steps off the edge of the bridge and falls straight downward.
Kate's height is negligible compared to the length of the bungee cord. Hence, she can be treated as a point particle.

Use (g) for the magnitude of the acceleration due to gravity.


How far below the bridge will Kate eventually be hanging, once she stops oscillating and comes finally to rest? Assume that she doesn't touch the water.




Homework Equations


Fs=-kx
Ws=.5kx2
Ei=Ef


The Attempt at a Solution


i'm not really sure...i know i have to use conservation of energy so this is what i tried
.5kx2+.5mvi2+mgh1=.5mvf2+mgh2
.5kx2=.5mvf2+2mgL
x=sqrt(mvf2+2mgL)

I don't think that conservation of energy is the way to approach this problem. Instead, think about the fact that if she is at rest, her acceleration is zero. How can that be used to solve the problem?