Calculating the Maximum Displacement of Kate's Bungee Jump

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SUMMARY

The discussion centers on calculating the maximum displacement of Kate's bungee jump using principles of physics, specifically conservation of energy and the properties of springs. The bungee cord behaves as an ideal spring with a spring constant (k), and Kate's mass (m) and the height of the bridge (h) are critical factors. The equations of motion and energy conservation are employed to determine how far below the bridge Kate will hang once she comes to rest, emphasizing the need to consider her acceleration at rest.

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  • Understanding of Hooke's Law and spring constants (k)
  • Knowledge of conservation of energy principles in physics
  • Familiarity with basic kinematics and dynamics
  • Ability to manipulate algebraic equations for solving physics problems
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  • Study the application of Hooke's Law in real-world scenarios
  • Learn about energy conservation in mechanical systems
  • Explore the dynamics of oscillatory motion and damping effects
  • Investigate the mathematical modeling of spring-mass systems
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cj3
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Homework Statement


Kate, a bungee jumper, wants to jump off the edge of a bridge that spans a river below. Kate has a mass (m) , and the surface of the bridge is a height (h) above the water. The bungee cord, which has length (L) when unstretched, will first straighten and then stretch as Kate falls.

Assume the following:

The bungee cord behaves as an ideal spring once it begins to stretch, with spring constant (k)
Kate doesn't actually jump but simply steps off the edge of the bridge and falls straight downward.
Kate's height is negligible compared to the length of the bungee cord. Hence, she can be treated as a point particle.

Use (g) for the magnitude of the acceleration due to gravity.


How far below the bridge will Kate eventually be hanging, once she stops oscillating and comes finally to rest? Assume that she doesn't touch the water.




Homework Equations


Fs=-kx
Ws=.5kx2
Ei=Ef


The Attempt at a Solution


i'm not really sure...i know i have to use conservation of energy so this is what i tried
.5kx2+.5mvi2+mgh1=.5mvf2+mgh2
.5kx2=.5mvf2+2mgL
x=sqrt(mvf2+2mgL)
 
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Hi cj3,

cj3 said:

Homework Statement


Kate, a bungee jumper, wants to jump off the edge of a bridge that spans a river below. Kate has a mass (m) , and the surface of the bridge is a height (h) above the water. The bungee cord, which has length (L) when unstretched, will first straighten and then stretch as Kate falls.

Assume the following:

The bungee cord behaves as an ideal spring once it begins to stretch, with spring constant (k)
Kate doesn't actually jump but simply steps off the edge of the bridge and falls straight downward.
Kate's height is negligible compared to the length of the bungee cord. Hence, she can be treated as a point particle.

Use (g) for the magnitude of the acceleration due to gravity.


How far below the bridge will Kate eventually be hanging, once she stops oscillating and comes finally to rest? Assume that she doesn't touch the water.




Homework Equations


Fs=-kx
Ws=.5kx2
Ei=Ef


The Attempt at a Solution


i'm not really sure...i know i have to use conservation of energy so this is what i tried
.5kx2+.5mvi2+mgh1=.5mvf2+mgh2
.5kx2=.5mvf2+2mgL
x=sqrt(mvf2+2mgL)

I don't think that conservation of energy is the way to approach this problem. Instead, think about the fact that if she is at rest, her acceleration is zero. How can that be used to solve the problem?
 

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