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Calculating the molarity of ions

  • Thread starter Turquoise
  • Start date
  • #1
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Homework Statement


When a reaction mixture with a total volume of 4 L that contains 9.99 g of solid CaSO4 was stoichiometrically produced as per the balanced equation with 2.50 L of aqueous Ca2+, what molarity (M) of Ca2+ was required?

Al2(SO4)3(aq) + 3 CaBr2(aq) → 2 AlBr3(aq) + 3 CaSO4(s)


Homework Equations


Stoichiometric ratios.


The Attempt at a Solution


Conversion of CaSO4 to mols = 1.36 mols
molar mass = 340.0 mol/L
After this, I don't know how to find the molarity of the Ca2+ ions...
 

Answers and Replies

  • #2
Borek
Mentor
28,441
2,838
Not sure if I understand what you are asking. I assume you mean you need to know what was molarity of Ca2+ solution if mass of precipitated calcium sulfate was 9.99g.

First - 9.99g is not 1.36 mole.

Second - concentration is moles/volume.

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