Calculating the Resulting Speed of a Student on a Turntable

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The discussion revolves around calculating the speed of a student walking on a frictionless turntable that comes to rest as the student walks. The initial setup involves a student with a mass of 40 kg on a turntable with a diameter of 5 m and mass of 400 kg, initially rotating at 2 revolutions per minute. Using the conservation of angular momentum, the student’s final angular velocity was calculated to be approximately 1.254 rad/s, leading to a resulting speed of about 3.135 m/s. The student is confirmed to be walking in the counterclockwise direction. The method used for the calculations appears correct, although the poster expresses concern about the simplicity of the problem given its point value.
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Homework Statement


A student of mass m=40 kg is standing on the edge of a uniform, frictionless turntable, with diameter d = 5m and mass M=400 kg. The student and the turntable are initially rotating counterclockwise together about a fixed axis through the center of the turntable with an angular velocity of wi = 2 rev/min.
The student now start to walk around the edge of the turntable so that the turntable comes to rest. What is the resulting speed v of the student relative to someone standing next to the turntable? In what direction is the student walking, clockwise or counter clockwise?

Homework Equations


conversion of rev/min to rad/s = rev/min * 1min/60s * 2(pi)/1rev
Conservation of angular momentum:
Li = Lf


The Attempt at a Solution


(Iturntable + Istudent)wi = Iturntable(wf) + Istudent(wfinal for student)
( (1/2)(400)(2.5)2 + (40)(2.5)2) (.209) = ( (1/2)(400)(2.5)2) (0) + ( (40)(2.5)2 ) wf

Solve for wf and I got 1.254 rad/s
Then use v = (r)wf = (2.5)(1.254) = 3.135 m/s
The student is walking in the counterclockwise direction

Can someone let me know if this is right? I thought it was too easy for a 30 point question
 
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I didn't plug in the numbers, but the method looks OK.
 
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