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For this question, I have solved letters a, b and c. I'm stuck at letter d.
Two point charges ql = +2.40 nC and q2 = -6.50 nC are 0.100 m apart. Point A is midway between them; point B is 0.050 m from ql and 0.060 m from q2 (Fig). Take the electric potential to be zero at infinity. Find
(a) The potential at point A;
(b) The potential at point B;
(c) The work done by the electric field on a charge of 2.50 nC that travels from point B to point A.
(d) The speed of the 2.50 nC when it reaches point A, if it starts from rest at point B
KE = 1/2 m v2 ?
I have solved a, b and c
a) VA = -737 V
b) VB = -704 V
c) WB->A = +8.2 x 10-8 J
Now I'm stuck at letter D, how do i find the speed? I assume that I might need the equation of KE = 1/2 m v2.. But I don't know how to do it.
What I did was to put +8.2 x 10-8 J as my KE. However, I do not have a mass, so how do I do this?
Homework Statement
Two point charges ql = +2.40 nC and q2 = -6.50 nC are 0.100 m apart. Point A is midway between them; point B is 0.050 m from ql and 0.060 m from q2 (Fig). Take the electric potential to be zero at infinity. Find
(a) The potential at point A;
(b) The potential at point B;
(c) The work done by the electric field on a charge of 2.50 nC that travels from point B to point A.
(d) The speed of the 2.50 nC when it reaches point A, if it starts from rest at point B
Homework Equations
KE = 1/2 m v2 ?
The Attempt at a Solution
I have solved a, b and c
a) VA = -737 V
b) VB = -704 V
c) WB->A = +8.2 x 10-8 J
Now I'm stuck at letter D, how do i find the speed? I assume that I might need the equation of KE = 1/2 m v2.. But I don't know how to do it.
What I did was to put +8.2 x 10-8 J as my KE. However, I do not have a mass, so how do I do this?